C program to print box number pattern of 1 with 0 center

Write a C program to print the given box number pattern of 1 with 0 center using loop. How to print box number pattern of 1's with 0 as center using for loop in C programming. Logic to print box number pattern with different center using for loop in C program.

Example

Input

Input rows: 5
Input columns: 5

Output

11111
11111
11011
11111
11111

Required knowledge

Basic C programming, Loop

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Logic to print box number pattern

In the above given pattern for every row and column 1 is printed except for the center row and column. Hence, to print this pattern we only need to focus on condition of center row and column.
Below is the step by step descriptive logic to print given pattern.

  1. Input number of rows and columns from user. Store it in some variable say rows and cols.
  2. Run an outer loop from 1 to rows, to iterate through rows. The loop structure should look like for(i=1; i<=rows; i++).
  3. Run an inner loop from 1 to cols, to iterate through cols. The loop structure should look like for(j=1; j<=cols; j++).
  4. Inside the inner before printing any number check the central row and column condition. Which is if(i==rows/2 && j==cols/2) then print 0, otherwise print 1.
  5. Finally, move to next life after printing all columns of a row.

Program to print box number pattern of 1's with 0 center

/**
 * C program to print box number pattern of 1's with 0 as center
 */

#include <stdio.h>

int main()
{
    int rows, cols, i, j;
    int centerRow, centerCol;

    /* Input rows and columns from user */
    printf("Enter number of rows: ");
    scanf("%d", &rows);
    printf("Enter number of columns: ");
    scanf("%d", &cols);

    /* Find center row and column */
    centerRow = (rows + 1) / 2;
    centerCol = (cols + 1) / 2;

    for(i=1; i<=rows; i++)
    {
        for(j=1; j<=cols; j++)
        {
            if(centerCol == j && centerRow == i)
            {
                printf("0");
            }
            else if(cols%2 == 0 && centerCol+1 == j)
            {
                if(centerRow == i || (rows%2 == 0 && centerRow+1 == i))
                    printf("0");
                else
                    printf("1");
            }
            else if(rows%2 == 0 && centerRow+1 == i)
            {
                if(centerCol == j || (cols%2 == 0 && centerCol+1 == j))
                    printf("0");
                else
                    printf("1");
            }
            else
            {
                printf("1");
            }
        }

        printf("\n");
    }

    return 0;
}

Output

Enter number of rows: 5
Enter number of columns: 5
11111
11111
11011
11111
11111

Happy coding 😉

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