Write a C program to input any number from user and find total number of leading zeros of the given number (in binary representation) using bitwise operator. How to find total number of leading zeros of a given number (in binary representation) using bitwise operator in C programming. Finding total number of leading zeros of a given number using C programming.

**Example**

**Input**

Input any number: 22

**Output**

Output leading zeros: 27 (using 4 byte signed integer)

## Required knowledge

Basic C programming, Bitwise operator, If else, Loop

## Program to count leading zeros in a binary number

```
/**
* C program to count leading zeros in a binary number using bitwise operator
*/
#include <stdio.h>
#define INT_SIZE sizeof(int) * 8
int main()
{
int num, count, msb, i;
// Input a number from user
printf("Enter any number: ");
scanf("%d", &num);
count = 0;
// Equivalent to
// 10000000 00000000 00000000 00000000
msb = 1 << (INT_SIZE - 1);
// Iterate over each bit
for(i=0; i<INT_SIZE; i++)
{
// If a leading set bit is found
if((num << i) & msb)
{
// No need to run further
break;
}
count++;
}
printf("Total number of leading zeros in %d is %d", num, count);
return 0;
}
```

Below is another short and effective approach to solve the program.

## Program to count leading zeros in a binary number 2

```
/**
* C program to count leading zeros in a binary number using bitwise operator
*/
#include <stdio.h>
#include <limits.h> // Used for INT_MAX
int main()
{
int num, count;
// Input a number from user
printf("Enter any number: ");
scanf("%d", &num);
count = 0;
while(!(num & (~INT_MAX)))
{
count++;
num <<= 1;
}
printf("Total number of leading zeros = %d", count);
return 0;
}
```

Output

Enter any number: 22 Total number of leading zeros in 22 is 27

**Note:** Output may be different on different compilers since since size of data types are machine dependent.

Happy coding 😉

<pre><code> ----Your Source Code---- </code></pre>