C program to count total number of nodes in Singly Linked List

Write a C program to create a singly linked list of n nodes and count total number of nodes in given linked list. How to count total number of nodes in a linked list in C. Algorithm to count total nodes in a singly linked list.

Singly linked list

Required knowledge

Basic C programming, Functions, Singly Linked List, Dynamic memory allocation

Algorithm to count number of nodes in Singly Linked List

Algorithm to count number of nodes in Singly Linked List
%%Input : head node of the linked list
Begin:
    count ← 0
    If (head != NULL) then
        temphead
        While (temp != NULL) do
            countcount + 1
            temptemp.next
        End while
    End if
    write ('Total nodes in list =' + count)
End

Program to count number of nodes in Singly Linked List

/**
 * C program to count number of nodes of Singly Linked List
 */

#include <stdio.h>
#include <stdlib.h>


/* Structure of a node */
struct node {
    int data;          // Data
    struct node *next; // Address
}*head;


void createList(int n);
int countNodes();
void displayList();


int main()
{
    int n, total;

    /*
     * Create a singly linked list of n nodes
     */
    printf("Enter the total number of nodes: ");
    scanf("%d", &n);
    createList(n);

    printf("\nData in the list \n");
    displayList();

    /* Count number of nodes in list */
    total = countNodes();

    printf("\nTotal number of nodes = %d\n", total);

    return 0;
}


/*
 * Create a list of n nodes
 */
void createList(int n)
{
    struct node *newNode, *temp;
    int data, i;

    head = (struct node *)malloc(sizeof(struct node));

    /*
     * If unable to allocate memory for head node
     */
    if(head == NULL)
    {
        printf("Unable to allocate memory.");
    }
    else
    {
        /*
         * Read data of node from the user
         */
        printf("Enter the data of node 1: ");
        scanf("%d", &data);

        head->data = data; // Link data field with data
        head->next = NULL; // Link address field to NULL

        temp = head;

        /*
         * Create n nodes and adds to linked list
         */
        for(i=2; i<=n; i++)
        {
            newNode = (struct node *)malloc(sizeof(struct node));

            /* If memory is not allocated for newNode */
            if(newNode == NULL)
            {
                printf("Unable to allocate memory.");
                break;
            }
            else
            {
                printf("Enter the data of node %d: ", i);
                scanf("%d", &data);

                newNode->data = data; // Link the data field of newNode with data
                newNode->next = NULL; // Link the address field of newNode with NULL

                temp->next = newNode; // Link previous node i.e. temp to the newNode
                temp = temp->next;
            }
        }

        printf("SINGLY LINKED LIST CREATED SUCCESSFULLY\n");
    }
}


/*
 * Counts total number of nodes in the list
 */
int countNodes()
{
    int count = 0;
    struct node *temp;

    temp = head;

    while(temp != NULL)
    {
        count++;
        temp = temp->next;
    }

    return count;
}


/*
 * Displays the entire list
 */
void displayList()
{
    struct node *temp;

    /*
     * If the list is empty i.e. head = NULL
     */
    if(head == NULL)
    {
        printf("List is empty.");
    }
    else
    {
        temp = head;
        while(temp != NULL)
        {
            printf("Data = %d\n", temp->data); // Print data of current node
            temp = temp->next;                 // Move to next node 
        }
    }
}

Output

Enter the total number of nodes: 5
Enter the data of node 1: 10
Enter the data of node 2: 20
Enter the data of node 3: 30
Enter the data of node 4: 40
Enter the data of node 5: 50
SINGLY LINKED LIST CREATED SUCCESSFULLY

Data in the list
Data = 10
Data = 20
Data = 30
Data = 40
Data = 50

Total number of nodes = 5

Happy coding 😉

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