C program to check whether a number is divisible by 5 and 11 or not

Write a C program to check whether a number is divisible by 5 and 11 or not using if else. How to check divisibility of any number in C programming. C program to enter any number and check whether it is divisible by 5 and 11 or not. Logic to check divisibility of a number in C program.

Example

Input

Input number: 55

Output

Number is divisible by 5 and 11

Required knowledge

Basic programming, If else

Logic to check divisibility of a number

Checking divisibility of a number means that the number is exactly divisible by some other number leaving no remainder. To check divisibility of a number, we need to check if remainder is 0 or not. If it is zero then only the number is exactly divisible otherwise not.

C programming supports an operator known as modulo % operator. Modulo operator returns remainder.
For example:

5 % 2 = 1 (Since 5/2 leaves 1 as remainder)
2 % 5 = 2 (Since 5 goes in 0 times leaving remainder 2)
8 % 2 = 0 (Since 8/2 leaves 0 as remainder)

Below is the step by step descriptive logic to check whether a number is divisible by 5 and 11 or not.

  1. Input a number from user. Store it in some variable say num.
  2. If num % 5 == 0 and num % 11 == 0. Then the number is exactly divisible by 5 and 11.

Let us implement the logic.

Program to check divisibility

/**
 * C program to check divisibility of any number
 */

#include <stdio.h>

int main()
{
    int num;

    /* Input number from user */
    printf("Enter any number: ");
    scanf("%d", &num);


    if((num % 5 == 0) && (num % 11 == 0))
    {
        printf("Number is divisible by 5 and 11");
    }
    else
    {
        printf("Number is not divisible by 5 and 11");
    }

    return 0;
}

Output

Enter any number: 55
Number is divisible by 5 and 11

Happy coding 😉

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